x^2+10x/10-2x+5/2=20

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Solution for x^2+10x/10-2x+5/2=20 equation: 



x^2+10x/10-2x+5/2=20

We move all terms to the left:

x^2+10x/10-2x+5/2-(20)=0

determiningTheFunctionDomain
x^2+10x/10-2x-20+5/2=0

We add all the numbers together, and all the variables

x^2-2x+10x/10-20+5/2=0

We calculate fractions

There is no solution for this equation

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